(x+1)^2/3-(9x+1)^1/3=0

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Solution for (x+1)^2/3-(9x+1)^1/3=0 equation: 


x in (-oo:+oo)

((x+1)^2)/3-(((9*x+1)^1)/3) = 0

((x+1)^2)/3-((9*x+1)/3) = 0

((x+1)^2)/3+(-1*(9*x+1))/3 = 0

(x+1)^2-1*(9*x+1) = 0

x^2-7*x = 0

x^2-7*x = 0

x*(x-7) = 0

x-7 = 0 // + 7

x = 7

x*(x-7) = 0

(x*(x-7))/3 = 0

(x*(x-7))/3 = 0 // * 3

x*(x-7) = 0

( x-7 )

x-7 = 0 // + 7

x = 7

( x )

x = 0

x in { 7, 0 }

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